0=6t-0.24t^2

Solution for 0=6t-0.24t^2 equation:

0=6t-0.24t^2

We move all terms to the left:

0-(6t-0.24t^2)=0

We add all the numbers together, and all the variables

-(6t-0.24t^2)=0

We get rid of parentheses

0.24t^2-6t=0

a = 0.24; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·0.24·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*0.24}=\frac{0}{0.48}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*0.24}=\frac{12}{0.48}
=25
$